Web28 feb. 2024 · Step-by-step explanation: Sec ( (x-y)/ (x + y)) = a (x-y)/ (x + y) = Sec⁻¹ (a) Differentiating wrt x => (x - y) ( - 1/ (x + y)²) (1 + dy/dx) + (1 - dy/dx)/ (x + y) = 0 multiplying by (x + y)² => (y - x) (1 + dy/dx) + (1 - dy/dx) (x + y) = 0 => y + ydy/dx - x - xdy/dx + x - xdy/dx + y - ydy/dx = 0 => 2y = 2xdy/dx => dy/dx = 2y/2x => dy/dx = y/x Web9 jan. 2024 · If dy/dx = x^2y^2, then d^2y/dx^2 =. will be the answer. To find the second derivative, differentiate the expression again by using partial differentiation, Therefore, …
Find dy/dx y=x^2+2 Mathway
WebAnswer (1 of 3): Solution is y*x^2 -tan(x) +y^2 = 0 ———————————————————————————————————— This ... Web9 nov. 2024 · If y = (sec^-1 x)^2, then show that x^2 (x^2 - 1)d^2y/dx^2 + (2x^3 - x)dy/dx = 2. ← Prev Question Next Question →. 0 votes. 54.7k views. asked Nov 9, 2024 in … comedy series on showtime
Ex 5.3, 4 - Find dy/dx in, xy + y2 = tan x + y - Chapter 5 - teachoo
Web10 sep. 2024 · If. dy dx = 2x+y − 2x 2y, d y d x = 2 x + y − 2 x 2 y, dy/dx = 2x+y - 2x/2y, y (0) = 1, then y (1) is equal to : (1) log2 (2 + e) (2) log2 (1 + e) (3) log2 (2e) (4) log2 (1 + e2 ) … Web30 mrt. 2024 · Ex 5.3, 12 - Chapter 5 Class 12 Continuity and Differentiability (Term 1) Last updated at March 30, 2024 by Teachoo. Get live Maths 1-on-1 Classs - Class 6 to 12. … Web18 jun. 2024 · Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site comedy set in hythe